2x^2+0.58x-0.058=0

Solution for 2x^2+0.58x-0.058=0 equation:

2x^2+0.58x-0.058=0

a = 2; b = 0.58; c = -0.058;
Δ = b2-4ac
Δ = 0.582-4·2·(-0.058)
Δ = 0.8004
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.58)-\sqrt{0.8004}}{2*2}=\frac{-0.58-\sqrt{0.8004}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.58)+\sqrt{0.8004}}{2*2}=\frac{-0.58+\sqrt{0.8004}}{4}
$